Fix issue #391: Add some documentation to indicate that a default constructor must be explicitly declared in a user-defined serializable type in order for it to be serializable.
Patch by: me
Review by: gwt.team.morrildl
git-svn-id: https://google-web-toolkit.googlecode.com/svn/trunk@437 8db76d5a-ed1c-0410-87a9-c151d255dfc7
diff --git a/doc/src/com/google/gwt/doc/DeveloperGuide.java b/doc/src/com/google/gwt/doc/DeveloperGuide.java
index 7db7e7f..23bdc1d 100644
--- a/doc/src/com/google/gwt/doc/DeveloperGuide.java
+++ b/doc/src/com/google/gwt/doc/DeveloperGuide.java
@@ -1830,9 +1830,11 @@
* <li>it is assignable to
* {@link com.google.gwt.user.client.rpc.IsSerializable}, either because it
* directly implements the interface or because it derives from a superclass
- * that does, and </li>
+ * that does</li>
* <li>all non-<code>transient</code> fields are themselves
- * serializable.</li>
+ * serializable, and</li>
+ * <li>it explicitly defines a default constructor, which is a constructor that is
+ * declared to be public and takes no arguments</li>
* </ol>
*
* The <code>transient</code> keyword is honored, so values in transient
@@ -1911,6 +1913,14 @@
* @gwt.typeArgs <java.lang.String,java.lang.String>
*/
public Map mapOfStringToString;
+
+ /**
+ * Default Constructor. The Default Constructor's explicit declaration
+ * is required for a serializable class.
+ *
+ */
+ public MyClass() {
+ }
}
/**
